# Chips and dip

1. Jul 30, 2008

1. The problem statement, all variables and given/known data
a chip is dipped into dip and bottoms out in a circle with radius r. A flavor crystal on the chip is put under twice the normal gravity. If r = .5m, how fast is the chip traveling at the bottom of the dip. Neglect the mass of the chip.

2. Relevant equations

3. The attempt at a solution

My answer is taking 9.8 *2 which is 19.6 m/s. Is this correct? It seems to easy. But dont we need to take into account the mass of the chip?

2. Jul 30, 2008

### HallsofIvy

Staff Emeritus
The acceleration due to gravity is 9.8 m/s2, not m/s and is not a velocity. In any case, "is put under twice the normal gravity" refers to a force not acceleration.

I frankly don't understand the problem- unless it is a very awkward way of asking what velocity something will have after starting from 0 velocity and moving 0.5 m at acceleration 19.6 m/s2. If that is the case, you need equations for velocity and distance with constant acceleration. How long will it take to go .5 m with constant 19.6 m/s2 acceleration? How will the velocity have changed in that time?

(Chip and dip? And the bowl of dip has a 50 cm radius? How big is the bottle of beer?)

3. Jul 30, 2008