Dear PF,(adsbygoogle = window.adsbygoogle || []).push({});

Could anyone help me to understand the following issue:

I dont understand the formation of Goldston bosons in chiral symmmetry breaking. Namely - suppose there is only fermion fields Lagrangian and due to some reasons the fermion field obteins VEV - <0|psi^bar psi|0> is non zero. And left/right chiral symmetry is reduced to its diagonal group.

I dont understant how Goldstone bosons are formed - I mean as folows"

In Scalar field case if we have multiple fields phi1, phi2, phi3.... and when

this scalalar field develops some VEV - v, then for convience we can put only phi1 equals to this VEV -v, rest fields we can put zero...we will say this VEV of field phi1 is v, VEVs of rest field are zero: <0|phi1|0>=v,

<0|phi2|0>=0 etc. We say we have phi1 massive scalar field and rest Goldsone Bosons from Broken Symmetry.

So I dont understand what happens when suppose fermion fields develop VEV.

Thanks

George

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# Chiral Symmetry Breaking

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