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Chocolate logs again

  1. May 12, 2008 #1
    i've got a logashizm problem to this point

    the log is base 2


    log (x(x+3)^2 / (4x+2)) = 1

    apparently x(x+3)^2 / (4x+2) = 2

    no idea why, halp?

    thx


    god damn it, nvm

    2^1 = (x(x+3)^2 / (4x+2)) when you take the damn log out.
     
    Last edited: May 12, 2008
  2. jcsd
  3. May 12, 2008 #2
    exactly
     
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