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Chocolate logs again

  • Thread starter DeanBH
  • Start date
  • #1
82
0
i've got a logashizm problem to this point

the log is base 2


log (x(x+3)^2 / (4x+2)) = 1

apparently x(x+3)^2 / (4x+2) = 2

no idea why, halp?

thx


god damn it, nvm

2^1 = (x(x+3)^2 / (4x+2)) when you take the damn log out.
 
Last edited:

Answers and Replies

  • #2
63
0
exactly
 

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