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Choose a voltage V <2.5 V

  • Thread starter Mosaness
  • Start date
  • #1
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1.Choose a voltage v < 2.5 V and values for the resistors R1, R2, R3, and R4 in
the circuit of Fig. 3.90 so that i1 =1 A, i2 =1.2 A, i3 =8 A, and i4 = 3.1 A.




Homework Equations



KCL/KVL/OHms Law



The Attempt at a Solution



If Is = I1 + I2 + I3 + I4,

Then, Is = [itex]\frac{v}{Req}[/itex]

Req = [itex]\frac{1}{R1}[/itex] + [itex]\frac{1}{R2}[/itex] + [itex]\frac{1}{R3}[/itex] + [itex]\frac{1}{R4}[/itex].

After this, I get stuck...
 

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Answers and Replies

  • #2
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You're over thinking the problem. For parallel branches, the voltage is the same to all branches of the node. For simplicity choose 1V and for R1 choose 1 ohm so that I1 = 1A. Now you have the voltage and current for each branch so just solve for resistance via ohm's law.
 
  • #3
92
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You're over thinking the problem. For parallel branches, the voltage is the same to all branches of the node. For simplicity choose 1V and for R1 choose 1 ohm so that I1 = 1A. Now you have the voltage and current for each branch so just solve for resistance via ohm's law.
So because we can choose any v that is less than 2.5V, you picked 1V correct?
 
  • #4
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Taking V as 1A and using the given values for the currents, I solved for R1, R2, R3, and R4:

R1 = 1V/1A = 1Ω

R2 = 1V/1.2A = 0.83Ω

R3 = 1V/8A = 0.125Ω

R4 = 1V/3.1A = 0.323Ω

Is this correct?
 
  • #5
157
0
Looks good. And if for some reason you need the voltage to be higher than you can just scale the resistance proportionately to maintain the same current.
 

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