AB is the diameter of a circle CD is a chord parallel to AB and 2CD=AB. The tangent at B meets the line AC produced at E. Prove that AE=2AB.(adsbygoogle = window.adsbygoogle || []).push({});

I'm finding no way to solve this ?

Still i thought of applying AE*CE=BE^{2}but that is not enough to slove the pro ???

Any other Hint to solve

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# Chord parallel to AB and 2CD=AB

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