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Circle cut in to equal areas.

  1. Jul 13, 2008 #1
    Given a circle radius 1 how do you divide it in to pieces of equal area using parallel lines?

    Maybe find the area under [tex]f(x) = \sqrt{1-x^{2}}[/tex]
    [tex]\int f(x)dx = \frac{1}{2} \left( x\sqrt{1-x^2} - \sin^{-1} (x) \right) [/tex]
    Well how do you find the location for the cuts if you need to divide the circle in to n pieces?

    This seems simple enough, but I can't figure it out.

    Is there a better way to do this, without calculus?
    Last edited: Jul 14, 2008
  2. jcsd
  3. Jul 14, 2008 #2
    I've got it now. Never mind.
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