# Circle cut in to equal areas.

1. Jul 13, 2008

### futurebird

Given a circle radius 1 how do you divide it in to pieces of equal area using parallel lines?

Maybe find the area under $$f(x) = \sqrt{1-x^{2}}$$
OK
$$\int f(x)dx = \frac{1}{2} \left( x\sqrt{1-x^2} - \sin^{-1} (x) \right)$$
Well how do you find the location for the cuts if you need to divide the circle in to n pieces?

This seems simple enough, but I can't figure it out.

Is there a better way to do this, without calculus?

Last edited: Jul 14, 2008
2. Jul 14, 2008

### futurebird

I've got it now. Never mind.