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Circle equation

  1. Apr 19, 2005 #1
    how would you find the equation of a circle : (x-p)^2 + (y-q)^2=r^2 with this given info:

    the circle passes through A(2,2) and B(5,3) and its centre is on the line defined by y=X+1
  2. jcsd
  3. Apr 19, 2005 #2
    Plug the two points in the equation and then you get an equation with p and q which should look like 3p+2q=13.

    since the center is on the line y=x+1, and the center of the circle is supposed to be (p,q). So q=p+1.

    then solve for the equation.
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