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Circuit analysis help

  1. Dec 1, 2008 #1
    I have to find the frequency response equation for this circuit in the attatched photo, but i dont know how to go about analysing it as I cannot see how to do voltage loop and node analysis does not work as the two nodes are not related so nothing can be eliminated from the generated equations... any suggestions?

  2. jcsd
  3. Dec 1, 2008 #2
    You can use the nodal method. You will need 4 equations. Designate the node between the two capacitors as v3 and the one between the two resistors as v4.

    Assume that a voltage source, Vi, is connected to node v1. Then the transfer function will be the ratio v2/Vi, in terms of the Laplace variable s.

    The first equation will be a constraint equation, simply saying that v1 is equal to Vi:

    1*v1 + 0*v2 + 0*v3 +0*v4 = Vi

    The third equation is derived from an application of KCL to node 3:

    (-s*C)*v1 + (-s*C)*v2 + (s*C+s*C+2/R)*v3 + 0*v4 = 0

    You should be able to fill in the 2nd and 4th equations.

    Then solve the linear system that results and the result you get for the voltage at node v2 will be Vi times a fraction in powers of s. That fraction is the transfer function.

    If you still have problems, show your work and you'll get more help.
  4. Dec 1, 2008 #3
    yeah thats what i started doing, then the next equation at node v4 will be:

    v1 + v2 - v4*(2RCs + 2) = 0

    which does not include any v3 terms so i cannot relate the two equations to eliminate v3.

    i cannot see any other nodes to analyse at this point so this is where i am stuck!
  5. Dec 1, 2008 #4


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    If you redraw the circuit, you will see that the first capacitor C, the R/2 resistor, the capacitor 2C and the first resistor R form a loop.
    In the same way, the second capacitor C, the R/2 resistor, the capacitor 2C and the second resistor R form a loop too.
    The voltages v1 and v2 are in the diagonals of the loops.
  6. Dec 1, 2008 #5
    You can get an equation for each of the 4 nodes.

    The equation at node 4 should be:

    (-1/R)*v1 + (-1/R)*v2 + 0*v3 + (2/R+2*s*c)*v4 = 0

    This equation has been simplified somewhat. You add all the currents in each component connected to the node and equate the sum to zero. Here's the very lowest level equation:

    1/R*(v4-v1) + 1/R*(v4-v2) + 2*s*C*(v4) = 0

    If you rearrange so that each node voltage, V1, v2, v3 and v4 has a single coefficient, you should get what I gave above.

    Use the same method to get the equation for node 2
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