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Introductory Physics Homework Help
Circuit analysis - two sources of emf
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[QUOTE="Miss_e101, post: 4899410, member: 529149"] [h2]Homework Statement [/h2] Hello all! I'm confused about an explanation that my textbook gives, and I'm wondering if someone can help me understand it. The passage is as follows: [I]A circuit consists of a 12 V battery with negligible internal resistance, in parallel with a charging unit with an emf of 15 V and internal resistance of 0.5 ohms. These two components provide power for all the car's electrical equipment. The car's battery maintains an emf of 12 V across it, because of its negligible internal resistance. [U]Hence, the terminal p.d. of the charging unit must also be 12 V.[/U] This implies that 3 V must be "lost volts" across the internal resistance of the charging unit. Since its internal resistance is 0.5 V, there must be a current of 6 A supplied by the charging unit.[/I] I'm confused specifically with the underlined statement - why does the p.d. of the charging unit have to be 12 V as well? Is it because the battery is actually powering the charging unit? Why then does it have an emf of 15 V? Any insight would be appreciated. Miss E. [h2]Homework Equations[/h2] Kirchoff's laws [h2]The Attempt at a Solution[/h2] n/a [/QUOTE]
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Circuit analysis - two sources of emf
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