1. The problem statement, all variables and given/known data Find the three currents in the image. 2. Relevant equations Khirkoffs laws Sum of currents equal zero. The potentials around a closed loop add up to zero. The equations given in the solution are [tex]-2I_1 + 12I_2+6=0[/tex] [tex]-12I_2+8 = 0[/tex] [tex]I_1+I_2+I_3=0[/tex] 3. The attempt at a solution When I tried to solve this I had the first equation to be [tex]-2I_1-12I_2+6=0[/tex], by doing a potential walk round the left subcircuit (?). Why should the second term be positive?