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Circuit analysis

  1. Apr 17, 2009 #1
    Problem and my attempt at the solution are in the figure below (red is my work):

    http://dl.getdropbox.com/u/364603/elec.png [Broken]
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Apr 17, 2009 #2

    rl.bhat

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    You can convert the parallel combination of current and resistance to a series combination of voltage and resistance. Equivalent voltage IR.
     
  4. Apr 17, 2009 #3
    Yes, I get 300 V and 50 ohm on the right then (if I remember correctly to do that) and this gives me 3A running. But, can you spot any mistake in my equation.

    It works good if I use -6, that gives V = 150 V or if I use other methods but I remember making this same mistake a year ago. I think I am missing something fundamental. I don't want to repeat it when solving complex circuits.
     
  5. Apr 18, 2009 #4

    rl.bhat

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    In circuit analysis we can use different methods. Usually source conversion and mesh analysis is easy to do. I have solved by source conversion.
    In mesh analysis, assign one current to each mesh and apply Kirchhoff law to find the current in each mash.
     
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