KVL, KCL, Ohm's law, voltage divider
The Attempt at a Solution
The equivlent resistance of the circuit is 25ohms. Therefore the current flowing through i2 is 20volts/25ohms = 0.8A
using KCL at the top node, 3A + i1 = .8, therefore i1 =-2.2A
The answers at the back of the book however say that i1 should be -2A, and i1 should be 1A.
Where did i go wrong, or does the book have a mis-print?
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