Circuit analysis

  • Engineering
  • Thread starter fran1942
  • Start date
  • #1
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Hello, I have tried really hard to understand this circuit but I just cant grasp it.

I am trying to understand how V2 comes to 6 volts ie. where does the 3amp come from that is multiplied by the value of V2 to give 6 volts.
It would help a lot if I could see the linear equation which gives 3 amps for the relevant loop.

Thanks kindly for any help with this.
 

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Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
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hello fran1942! :smile:

use KCL to find the current through the bottom wire, directly under the 2Ω …

how much is that, and how does it help you to find the current through the 2Ω itself? :wink:
 
  • #3
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OK thanks. I see that current will be the combination of the 2 and the 1, making 3. Is it as simple as that ?

The main thing bugging me was that I could not work out the linear equation to give that 3amps.
Could someone please help with that equation.

Thanks again.
 
  • #4
tiny-tim
Science Advisor
Homework Helper
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… I could not work out the linear equation to give that 3amps.

not following you …

the KCL linear equation for that junction under I2 is 1 + 2 = 3 …

what is worrying you about that? :confused:
 

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