Find the current on the 20 ohm resistor.
The Attempt at a Solution
Well, I'm fairly positive that the two 10 ohm resistors will transport the same amount of current so:
25V - I*25 - I2*10 = 0
25V + I3*5 - 10*I2 = 0
I = 2*I2 + I3
When I solve using those equations, I get I2 = 1.36 A and I = .45 A (I is double of what it should be).
Could anyone look at my equations and tell me what's wrong?
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