1. The problem statement, all variables and given/known data The power supply in the circuit shown has V(t) = (120V)cos(ωt), where ω = 310 rad/s. Determine the current ﬂowing through the resistor at time t = 9.7 s, given R = 600 Ω, C = 18 mF, and I(0) = 0 A. As a reminder, Kirkhoﬀ’s voltage law for this circuit (Eq. 8-1.3 in the book) reduces to: dV/dt = R(dI/dt) + I/C. 2. Relevant equations 3. The attempt at a solution I've tried this about ten times and can't seem to get the right answer: I found dV/dt = -37200 Sin(wt) (i'll call it v' from now on) Rearranging the equation to make it in standard form: dI/dt + (1/RC)I = v'/R P= 1/RC = .0926 Q=v'/R = -62 Sin(wt) F = ∫p dt So e^F = e^.0926 t and e^-F = e^-.0926 t This equation was given in class for solving this type of DE: I = (e^-I)∫Q*e^F dt + c1*e^-F When plug this into mathematica, it gives me an imaginary answer Any ideas?