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Circuit for Hall effect sensor

  1. Oct 26, 2010 #1
    I recently bought a linear Hall effect sensor for measuring current, but I don't know how to make the circuit to measure the current, could anybody help me with this? Please tell me the circuit.
    By the way, I use the linear Hall effect sensor CSLA2EL by Honeywell.
    Thank you very much!
  2. jcsd
  3. Oct 26, 2010 #2
    Wow, that's not easy...the first google link I got was labeled "datasheet" but I couldn't find any electrical connection information on it.

    But I found a bunch of other datasheets here:
    http://www.datasheets.org.uk/CSLA2EL-datasheet.html [Broken]
    and one has a pinout buried deeply in the noise. Now I forget which link I clicked and followed and interpreted, but you should be able to find it too...

    It looks like they take a power supply of 8-16v and put out a voltage that is proportional to the current in the loop.
    Last edited by a moderator: May 5, 2017
  4. Oct 26, 2010 #3
    I think this is the datasheet for the Hall effect sensor in the unit. The calibration is in terms of the Gauss field in the toroid gap.


    See attached pdf for some info on electrical characteristics of current sensor Hall effect holder toroid.

    [added] The performance specs for the Hall effect sensor are for operating with a 12 volt dc input. I suggest using a 7812 3-pin regulator. The Hall effect sensor output is an ac output for an ac current input. The null output offset voltage for zero current input is 6 volts ± 0.6 volts. The output appears to be an npn transistor current-sourcing emitter.

    Bob S

    Attached Files:

    Last edited: Oct 26, 2010
  5. Aug 24, 2012 #4
  6. Aug 24, 2012 #5


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    Staff: Mentor

    This is almost a necropost spam post, but the link is actually pretty useful and on-topic for this old thread.
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