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**Question:**

A 0.25 x 10^-6 F capacitor is charged to 50V. It is then connected in series with a 25 ohm resistor and a 100 ohm resistor and alowed to discharge completely. How much energy is dissipated by the 25 ohm resistor ?

Attempt:

I found a formula in the textbook related to this question:

The resistors dissipate energy at the rate:

PR = I^2R = (Delta V)^2 / R

I don't know what to do next .... and if I'm using the right formula. Please somebody help.