A circuit contains two inductors of 6.0 mH inductance in series placed in parallel with an inductor of 8.0 mH inductance. After one of the 6.0 mH inductors burns out, the repair person wants to replace all three inductors with one inductor of equivalent inductance. What inductance should she use? 1. 3.0 mH 2. 4.8 mH 3. 3.4 mH 4. 11 mH 5. 20 mH Two 6 mH in series = L1+L2 = 6+6= 12mH this is in parallel with 8mH so,,total L = 12*8/20 = 4.8mH Is this correct???