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Circuit is driving me nuts

  1. Apr 28, 2012 #1
    Hi,

    I have attached a diagram of a wye connected motor load with open neutral. The circuit shows an inverter state with a DC-bus voltage from terminal A to G (ground). The following equations should hold:

    V_AN = Z*Ia + Ea
    V_GN = Z*Ib + Eb
    V_GN = Z*Ic + Ec
    Ia + Ib + Ic = 0
    Ea + Eb + Ec = 0 (back EMFs sum to zero)

    I want to prove that:

    Ea/Ia = Eb/Ib = Ec/Ic

    which would mean, according to:

    V_AN/Ia = Z + Ea/Ia
    V_GN/Ib = Z + Eb/Ib
    V_GN/Ic = Z + Ec/Ic

    that the impedance + back EMF in each phase can be replaced by the same effective impedance. I have verified this by simulation in LTspice.

    This is probably very simple, but it has been bothering me all day. Any help is greatly appreciated.

    Thanks!
     

    Attached Files:

  2. jcsd
  3. Apr 29, 2012 #2
    Err, so I made a huge mistake when I did the simulation, Ea/Ia = Eb/Ib = Ec/Ic can't be proven because it doesn't hold :>

    I was wondering why the phase voltages for the circuit I posted were the same for a passive circuit with equal phase impedances. This is naturally due to the fact that the phase voltages sum to zero in both cases (when back EMFs sum to zero):

    V_AN + 2*V_GN = Z*Ia + Ea + Z*Ib + Eb + Z*Ic + Ec = Z(Ia + Ib + Ic) + Ea + Eb + Ec =>

    V_AN + 2*V_GN = 0

    which would be the same for the passive circuit.

    If you took the time to mull over this, thank you, apologies :)
     
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