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**Circuit ....LOSt**

## Homework Statement

A sandard cell or 1080V gives a balance length of 512 mm on a potentiometer. If the p.d across a standard 10.0 (ohm) resistor in a circuir gives a balance length of 784 mm, calculate the current in the circuit with the 10.0 (ohm) resistor. Draw a circuit sketch og the two circuit arrangements required in the above case.

I am stuck here..am i going right?.please help someone..

## The Attempt at a Solution

E = k * 512*10^-3 (512 times ten to the power of minus 3)

V = E - Ir

V = k * 784*10^-3

V = IR I = V/R = V/10

E = V + Ir

K* 784*10^-3 = k * 512*10^-3 - K*784*10^-3(r)/10

K's cancel

784*10^-3(r)/10 = 784*10^-3 - 512*10^-3

= 0.0784r = 0.272

= 3.46(ohms)

.....what else do i do from here?