1. The problem statement, all variables and given/known data Find Vx. 2. Relevant equations KCL V=IR 3. The attempt at a solution First since the undrawn voltage source is in parallel with the 2 ohms resistor. Therefore, I concluded that the voltage source is also -3V For node labeled V1: Iin-(-3V/2ohms)+I from V3 to V1=0. (The first question is how can I get I in and I from V3 to V1?) For node labeled V3:7A=I from V3 to V1 + I entering the parallel part For the parallel part: V5-V6=Vx; Vx/6ohms+Is = I from V5 to V6. For node labeled V7: I from V5 to V6 + (-4Vx)-(-2V/2ohms)=0 ==> (V5-V6)/6ohms+Is-4(V5-V6)+1=0 (How do I find Is?) Would someone please give me some insight on this circuit? Many thanks in advance!