# Circuit problem, need help?

1. Sep 21, 2004

### ninaricci

circuit problem, plz need help??

Hi,
I am going to be so pleased if somebody helped me with the problem in the attached file
best wishes :surprised :surprised :surprised :surprised
here is my solution but i do not know where the mistake is
solution number 1

4-ix-vo/10=0
V of 20k = vo of 10 = 4Ix
Using eq 1…..4-ix-4Ix/10=0
4-1.4Ix=0
4=1.4Ix
4/1.4=Ix
= 2.86ma
Vo=4*2.86 = 11.4v

Solution number 2

Combing 10 kohm and 10 kohm = 20 since they are in series
Voltage of 20 kohm the resultant is = 4000Ix
4000Ix/20 = I of 20 kohm……200Ix = I of 20 kohm
Kcl
4mA-Ix –Iof vo = 0
4ma-Ix – 4000Ix/10
4ma-Ix – 400Ix = 0
4ma -401Ix =0
4ma = 401 Ix
4ma/401 = Ix
Ix= 0.00998mA
Vo = Io of vo * 10 kohm
4mA-0.00998-Io of vo = 0
Io of vo = 3. 99 ma
Vo = 3.99* 10 = 39 .9V
which solution is correct and if thre is amistake where is it

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Last edited: Sep 21, 2004
2. Sep 21, 2004

### enigma

Staff Emeritus
ninaricci,

please post what you've tried for this problem.

I'm moving the thread to homework help.

3. Sep 21, 2004

### Clausius2

Too late, I gave her an answer in the General Physics forum. She posted it there too.