Circuit problem, need help?

1. Sep 21, 2004

ninaricci

circuit problem, plz need help??

Hi,
I am going to be so pleased if somebody helped me with the problem in the attached file
best wishes :surprised :surprised :surprised :surprised
here is my solution but i do not know where the mistake is
solution number 1

4-ix-vo/10=0
V of 20k = vo of 10 = 4Ix
Using eq 1…..4-ix-4Ix/10=0
4-1.4Ix=0
4=1.4Ix
4/1.4=Ix
= 2.86ma
Vo=4*2.86 = 11.4v

Solution number 2

Combing 10 kohm and 10 kohm = 20 since they are in series
Voltage of 20 kohm the resultant is = 4000Ix
4000Ix/20 = I of 20 kohm……200Ix = I of 20 kohm
Kcl
4mA-Ix –Iof vo = 0
4ma-Ix – 4000Ix/10
4ma-Ix – 400Ix = 0
4ma -401Ix =0
4ma = 401 Ix
4ma/401 = Ix
Ix= 0.00998mA
Vo = Io of vo * 10 kohm
4mA-0.00998-Io of vo = 0
Io of vo = 3. 99 ma
Vo = 3.99* 10 = 39 .9V
which solution is correct and if thre is amistake where is it

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Last edited: Sep 21, 2004
2. Sep 21, 2004

enigma

Staff Emeritus
ninaricci,

please post what you've tried for this problem.

I'm moving the thread to homework help.

3. Sep 21, 2004

Clausius2

Too late, I gave her an answer in the General Physics forum. She posted it there too.