1. The problem statement, all variables and given/known data We are given: R1= 1[tex]\Omega[/tex] R2= 2[tex]\Omega[/tex] L = 3 mH C = 500 [tex]\mu[/tex]F If the voltage is kept at 4V what is the energy stored in the circuit after it has reached a steady state. There is a link posted to the circuit provided below. 2. Relevant equations energy stored in capacitor = 1/2Cv2 energy stored in inductor = 1/2Li2 3. The attempt at a solution Since you are given all the values you can just plug into the formula to find the energy stored in the capacitor. I got 0.004J. For the inductor I determined the current that flows through it which is 4V / 2[tex]\Omega[/tex] = 2A. I then used this value to compute the energy stored in the inductor, for that I got 0.006J. The total energy would be the sum of the two. This seems to be a simple problem but I'm just wondering if its a trick question since they want to know what the energy stored is after a long period of time.