Circuit question

  • Thread starter Lewis
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  • #1
Lewis
Hello, I'd really appreciate a hand with this question. The text of the question follows and there is an attachment with the referenced figure at the end. Thanks very much.

A battery is used to charge a capacitor through a resistor, as shown in Figure 28.19. Show that half the energy supplied by the battery is stored as internal energy in the resistor, and that half is stored in the capacitor.
 

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Answers and Replies

  • #2
you can get i(t) from the basic equations. then, integrate the heat dissipated in the resistor (that's what they mean by internal energy, if I understand correctly) - which depends upon the current - from time zero to time infinity. This should end up being equal to the energy stored in a fully charged capacitor.



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