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Circuit question

  1. Feb 17, 2006 #1
    Hello, I'd really appreciate a hand with this question. The text of the question follows and there is an attachment with the referenced figure at the end. Thanks very much.

    A battery is used to charge a capacitor through a resistor, as shown in Figure 28.19. Show that half the energy supplied by the battery is stored as internal energy in the resistor, and that half is stored in the capacitor.
     

    Attached Files:

  2. jcsd
  3. Feb 17, 2006 #2
    you can get i(t) from the basic equations. then, integrate the heat dissipated in the resistor (that's what they mean by internal energy, if I understand correctly) - which depends upon the current - from time zero to time infinity. This should end up being equal to the energy stored in a fully charged capacitor.



    Joe Andersen

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