Circuit Question

  • Thread starter sparkle123
  • Start date
  • #1
175
0
6a4c68ab.png


Due to the symmetry of the circuit there is no current through the resistor between the junctions (AF) and (DG) so the junctions (AF) and (DG) have the same potential.

I don't understand how this is true. The circuit is symmetrical left-right but not top-bottom. Isn't top-bottom symmetry what is required to eliminate current between AF and DG?
Thanks!
 

Answers and Replies

  • #2
I like Serena
Homework Helper
6,579
179
Hi sparkle123! :smile:

Due to the horizontal symmetry, all points in the circuit that are on the vertical center line have the same potential.
(There's as much resistance left as right of these points.)

When there is no potential difference, no current will flow.
 
  • #3
Delphi51
Homework Helper
3,407
11
The top branch with R1 and R1 leaves the AF junction half way between the potentials at E and B.

The bottom branch also has equal resistance on either side, splitting the potential to half way between E and B. The potentials at AF and DG are the same so there is no current from one to the other.

edit: didn't see your post before posting, I like Serena.
Great minds think alike?
 
  • #4
175
0
Thanks I like Serena and Delphi51! :)
(yes, great minds do think alike!)
 

Related Threads on Circuit Question

  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
10
Views
1K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
3
Views
1K
Replies
8
Views
1K
  • Last Post
Replies
6
Views
633
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
11
Views
840
  • Last Post
Replies
14
Views
1K
Top