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Hey guys so I'm new here but really need help with just with a confirmation on the answer on this question.

Two resistors R1 and R2 are connected in series and these are connected in series to a battery. If 20% of the power coming from the battery is dissipated through the R1 resistor, determine the ratio R1/R2.

R=V/I (just moved around Ohms Law)

Well since the resistor is in a series you normally would add them together. Since you lose 20% of the power through the first resistor you have 80% left. So I'm not positive but i figured you would just divide 20/80 and you end up with 0.25. Thanks for the help I appreciate it.

## Homework Statement

Two resistors R1 and R2 are connected in series and these are connected in series to a battery. If 20% of the power coming from the battery is dissipated through the R1 resistor, determine the ratio R1/R2.

## Homework Equations

R=V/I (just moved around Ohms Law)

## The Attempt at a Solution

Well since the resistor is in a series you normally would add them together. Since you lose 20% of the power through the first resistor you have 80% left. So I'm not positive but i figured you would just divide 20/80 and you end up with 0.25. Thanks for the help I appreciate it.

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