1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Circuit with diode

  1. Apr 14, 2013 #1
    I attached the circuit.
    I need to find I_1, Voltage drop across R1, voltage drop across R2, and I_2. We're assuming the diode is 'not' ideal.

    Vin=5V. R1=R2=1kohm
    R3=2kohm


    voltage across R2=Vin=5V
    I2=5/1kohm=5mA

    The real diode drops about 0.7 V. So using voltage divider gives voltage across R1=(R1/(R1+R3))*(5-0.7)=1.43V

    Then I1=1.43/1k=1.43mA


    Is this the right idea?
     

    Attached Files:

  2. jcsd
  3. Apr 14, 2013 #2

    phinds

    User Avatar
    Gold Member
    2016 Award

    without comment on the correctness of your specific numbers, let me ask you this:

    Do you feel that I2 = 5m in the same sense that I1 = 1.43ma. That is, other than magnitude, would they have the same waveform if graphed?
     
  4. Apr 14, 2013 #3
    I guess I don't see what you're asking.
    This is a DC signal.

    For an AC signal, the would not have the same wave form due to the diode.
     
  5. Apr 14, 2013 #4

    phinds

    User Avatar
    Gold Member
    2016 Award

    Hm ... why do you suppose a DC source is labeled "Vin, VAC ?"
     
  6. Apr 15, 2013 #5
    Ignore the AC part, that's for another problem.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Circuit with diode
  1. Diode Circuit (Replies: 3)

  2. Circuits with Diodes (Replies: 7)

  3. Circuits with diode (Replies: 9)

  4. Diodes in a circuit (Replies: 7)

  5. Diode circuit problem (Replies: 15)

Loading...