I attached the circuit. I need to find I_1, Voltage drop across R1, voltage drop across R2, and I_2. We're assuming the diode is 'not' ideal. Vin=5V. R1=R2=1kohm R3=2kohm voltage across R2=Vin=5V I2=5/1kohm=5mA The real diode drops about 0.7 V. So using voltage divider gives voltage across R1=(R1/(R1+R3))*(5-0.7)=1.43V Then I1=1.43/1k=1.43mA Is this the right idea?