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Circuits 1 ,hard proplem for me

  1. Sep 14, 2004 #1
    hi everyone

    i try to solve this proplem but only have mesh 2 and 3, i stuck at mesh 1,please anyone give me some advise ? or ways to solve this proplem, thanks first.

    Given :
    Is1= .75A, Beta =1 A/A , rho = 3ohm
    R1= 2 , R2 =2 , R3= 2, R4 =2, R5 =1, R6 =3
    http://viethost4u.com/toan/circuit1.GIF
     
  2. jcsd
  3. Sep 15, 2004 #2

    ehild

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  4. Sep 15, 2004 #3
    i cant; attach,because this site say the image too large,i think it work now
     
  5. Sep 15, 2004 #4

    ehild

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    For mesh1, you have

    i1=is2=beta*iy, and iy=i2-i3 (at R5). So the equation for mesh1 is:

    i1-beta*i2+beta*i3=0.

    Show me please what you got for mesh 2 and 3.

    ehild
     
  6. Sep 15, 2004 #5
    Here what i did:
    For mesh 2:
    (i2-i1)*R4 + (i2-is1)*R2 + (i2-i3)*R5 =0
    which i1,i2,is1,R2,R4,R5 are given

    For mesh 3:
    R6*i3 +(i3-i2)*R5 + vs3 = 0
    we have vs3 = 3ix
    but ix =-is1 -i2 ( KCL)

    Put them together and solve ==> i1,i2,i3

    thanks for repond
     
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