DC steady state circuit analysis: Consider the circuit shown below. The switch shown in the problem opens at time t = 0 seconds. If the circuit is in DC steady state at , find values for iL(0-), iL(0+), i(0-), i+, Vc(0-), Vc(0+). There is no RL or RC analysis to be performed on this problem. On your answer for the current, a positive value indicates current is flowing in the direction shown. A negative value for current will indicate that the current is flowing opposite the direction shown.
The Attempt at a Solution
Ok so I know that iL(0-)=iL(0+) because current is constant through an inductor. And I know that Vc(0-)=Vc(0+) because voltage across a conductor is constant.
I feel like I don't know some of the basic concepts I need to solve this. Is Is(t)=0 since the switch is up? Is the 26v voltage source the same as the voltage across the 10 ohm resistor? Vc is supposed to equal 6 volts and iL and i are supposed to be 1.5 amps. I can't quite figure it out :(
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