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Circuits dependent sources

  1. Jan 14, 2014 #1
    1. The problem statement, all variables and given/known data
    Determine Vy in the circuit of the below figure:
    (In attachment)


    2. Relevant equations
    ohms law
    resistance adding equations for parallel and series


    3. The attempt at a solution
    So I found Vx=(1.2A)(5ohms) = 6v
    Afterwards I computed the current supplier: (6)(0.1)=0.6 A
    Then I added the resistance of the parallel resistors and got 1.667 ohms
    Then found the voltage drop across it using the 1.2 A and get 2 v.
    Seeing how the parallel resistors share the same voltage, I computed the supposed current for each (without the dependent current supply) and get 1 A for the 2 ohm resistor.
    Then I added the 1 A to the 0.6 A from before, and then applied ohms law (1.6 A)(2 ohms) to get 3.2.

    This is my first time doing a problem regarding dependent sources, please let me know if I am missing any steps or using too many steps.

    Thanks.
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     

    Attached Files:

  2. jcsd
  3. Jan 14, 2014 #2

    berkeman

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    Staff: Mentor

    For some reason I'm not able to open the PDF file -- it says it is damaged or has other problems. Can you try uploading it again?
     
  4. Jan 14, 2014 #3
    I made it on paint, here's a PNG file.
     
  5. Jan 14, 2014 #4
    Sorry for the repost, but i don't think ti got though on my last reply. Here's the JPEG*
     

    Attached Files:

  6. Jan 14, 2014 #5

    gneill

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    Staff: Mentor

    One you know the current I then the potential drop across the 2 Ω resistor should be trivial by Ohm's law. You don't need any intermediate steps with parallel resistance calculations or anything else.
     
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