In the attachment (also given at bottom for your convenience) you can see the circuit diagram. We all know that the 5 ohm resistor is short-circuited so no current flows through the resistor. But if we apply Kirchoff's loop law with the following symbols:(adsbygoogle = window.adsbygoogle || []).push({});

i = current through DBAC from positive terminal of batterywe get,

i1 = current through CD from junction C

i-i1 = current through CEFD from E

from loop AEFBA,

5(i-i1) = 5 or i-i1 = 1from loop CEFDC,

5(i-i1) = 0 or i-i1 = 0Thus ambiguity arises.

Can anyone please explain me where I am going wrong ?

Also if we apply loop law to BDCAB,

5 = 0

Where is the fallacy here? (i mean, where am i wrong ? )

Thank you.

[PLAIN]http://img594.imageshack.us/img594/7609/circuit.jpg [Broken]

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# Circuits - Kirchoff's Law

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