The Attempt at a Solution
I found Vth
(V1 - V2)/2 + V1/10 + 2 = 0
(V2-6)/4 + (V2-4)/6 + (V2 - V1)/2 = 0
Solving for V1 I get -5/2 and V2 I get 1
V1 = Vth = -5/2
I believe this is correct. It's just if these two initial equations are wrong or correct. In the first equation I added the current entering the node close to a as V1. I wasn't sure how to handle the 5 ohm resistor.
I choose V2 as the node between the 2 ohm resistor, the 6 ohm resistor and the 6V power source.
I choose the ground reference node to be the whole right side.
I'm not sure how to procede and find the current across the short because drawing a wire to a and b results in a huge essential node.
Thanks for any help.