I have attached the problem along with the answers. I have a question on both of the questions. For the first question, if the diode is ideal, does that mean it's automatically "forward biased?" The problem statement says "assume the diode is ideal (i.e. has a 0V forward bias voltage), but I don't think that's necessarily stating it's forward biased, is it? A forward biased diode means that current is flowing from left to right (in this figure). The voltage to the left of the diode must be greater than the voltage to the right of the diode. My question is, the solutions assumed it's an ideal diode, but I don't understand how they could assume that without figuring if the voltage to the left of the diode is greater than the right. For the second question, when a capacitor just starts charging, it pretty much acts like a short right? And an inductor would act like a open.