itsmarasilly said:Homework Statement
A 610-kg racing car completes one lap in 14.3 s around a circular track with a radius of 60.0 m. The car moves at constant speed.
(a) What is the acceleration of the car?
(b) What force (Newtons) must the track exert on the tires to produce this acceleration?
Homework Equations
v = 2*Pi*Radius / Time
a = velocity^2 / Radius
T = 2(Pi)R / Velocity
The Attempt at a Solution
(2)(Pi)(60.0)/(14.3)=26.36
695.01^2 = 695.01 / 60 = Acceleration = 11.58
itsmarasilly said:i think Newtons are basically Kg m/s^2, if so, how do i figure that out from the information given? thanks a lot for your help
itsmarasilly said:fnet = m*a, so
fnet = 610 * 11.58
fnet = 7063.8 ?
Circular acceleration is the rate at which an object's velocity changes as it moves in a circular path. It is a vector quantity and is measured in units of meters per second squared (m/s²).
Circular acceleration is caused by a net force acting on an object moving in a circular path. This force, known as the centripetal force, is directed towards the center of the circle and is responsible for keeping the object in its circular motion.
The relationship between circular acceleration and force is described by Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration. In the case of circular motion, the centripetal force is equal to the mass of the object multiplied by its circular acceleration.
Circular acceleration can be calculated using the equation: a = v²/r, where a is the circular acceleration in m/s², v is the speed of the object in m/s, and r is the radius of the circular path in meters.
Some examples of circular acceleration and force in everyday life include a car turning a corner, a satellite orbiting the Earth, and a roller coaster looping around a track. These all involve a centripetal force acting on the object to maintain its circular motion.