A Ferris wheel of radius 42.0m is just starting up. At a given instant, a passenger on the edge of the wheel and passing through the lowest point of his circular motion is moving 3.25m/s and is gaining speed at a rate of 0.550m/s2. Find the magnitude and direction of the passenger's acceleration vector at this instant.
arad = v2/R
The Attempt at a Solution
I'll say that I have no clue what this question is actually asking. Considering, it gave the acceleration and 3.252/42 [tex]\neq[/tex] 0.550, which is the given acceleration. Thanks for any help.