Circular Acceleration problem

  • #1
658
2

Homework Statement


A Ferris wheel of radius 42.0m is just starting up. At a given instant, a passenger on the edge of the wheel and passing through the lowest point of his circular motion is moving 3.25m/s and is gaining speed at a rate of 0.550m/s2. Find the magnitude and direction of the passenger's acceleration vector at this instant.


Homework Equations


arad = v2/R


The Attempt at a Solution


I'll say that I have no clue what this question is actually asking. Considering, it gave the acceleration and 3.252/42 [tex]\neq[/tex] 0.550, which is the given acceleration. Thanks for any help.
 

Answers and Replies

  • #2
You've got two different accelerations in this problem, what you gotta do is compute the value and direction of the total acceleration experienced by the passenger.

Hint: where's the 3.25^2/42 acel. pointing to? and the 0.555 one?
I hope this helps.
 
  • #3
658
2
Yes, that makes a lot of sense. So, the given acceleration would be pointing along the x axis and the v2/R acceleration would be pointing in the y axis. Right?
 

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