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Circular acceleration

  • Thread starter lostinphys
  • Start date
  • #1
I'm sorry guys... i'm stuck again...
An automobile whose speed is increasing at a rate of 0.600 m/s2 travels along a circular road of radius 20.0 m. When the instantaneous speed of the automobile is 3.00 m/s, find the tangential acceleration component.
Magnitude.

... i know that the tangential acceleration = radius (angular acceleration) , but i am having trouble understanding the actual computation of tangential acceleration. i picked up a couple of books, and i'm still pretty lost.
 

Answers and Replies

  • #2
20
0
lostinphys said:
I'm sorry guys... i'm stuck again...
An automobile whose speed is increasing at a rate of 0.600 m/s2 travels along a circular road of radius 20.0 m. When the instantaneous speed of the automobile is 3.00 m/s, find the tangential acceleration component.
Magnitude.

... i know that the tangential acceleration = radius (angular acceleration) , but i am having trouble understanding the actual computation of tangential acceleration. i picked up a couple of books, and i'm still pretty lost.

hi there...

im new to this site.. sorry i cant help you w/ that problem... maybe you can help me with a simple question i have?
 
  • #3
Päällikkö
Homework Helper
515
10
Centripetal acceleration does not affect speed (it changes the direction of velocity).
I'd say the tangental acceleration is 0,6 m/s^2.


If 0,6 m/s^2 was, however, meant as the total acceleration:
If the instantaneous velocity at the given instant t is 3,00 m/s, what is the centripetal acceleration needed to keep the object on its circular orbit of 20m radius?
Tangental and centripetal acceleration are perpendicular. The given total acceleration is the hypotenuse.
 

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