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How far from the bottom of the chute does the ball land?

Height=2R

I got initial velocity=sqrt(2gR), and I plugged that into d=vit+1/2at^2, to give me 2R=sqrt(2gR)t+1/2gt^2, and I used the quadratic formula and got [-sqrt(2gR)+sqrt((2gR)-4gR))]/g, which simplifies to [sqrt(6gR)-sqrt(2gR)]/g. But, that was wrong...and I'm really not sure where I went wrong. Can someone tell me what the problem is here?