A pilot with mass m fles an airplane at a speed of v in a turn of radius r. Prove that angle of the wings of the airplane to the horizontal is tanQ=(VxV)/gr
The Attempt at a Solution
This was asked on my first exam last week.
Since it's tangent. All we need to get is the force, result will equal to (FxcosQ)/(FxSinQ)=(VxV)/gr?
I'm not getting anywhere with this? Can someone help me?