1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Circular motion and energy

  1. Feb 13, 2016 #1
    1. The problem statement, all variables and given/known data
    A)
    An object moving along the x axis is acted upon by a force Fx that varies with position as shown. How much work is done by this force as the object moves from x = 2 m to x = 8 m?
    B)
    A 50-kg child riding a Ferris wheel (radius of wheel R = 10 m) travels in a vertical circle. The wheel completes one revolution every 10 s. What is the magnitude of the force on the child by the seat at the highest point on the circular path?
    C)
    A 0.50-kg mass attached to the end of a string swings in a vertical circle (radius = 2.0 m). When the mass is at the lowestpoint on the circle, the speed of the mass is 12 m/s. What is the magnitude of the force of the string on the mass at this position?
    D)
    A 2.5-kg object falls vertically downward by 80 cm. How much work is done by the gravitational force on the object in this process?
    E)
    If vector A and B have magnitudes 12 and 15, respectively, and the angle between the two when they are drawn starting from the same point is 110, what is the scalar product of these two vectors?


    2. Relevant equations
    a=v^2/r
    W=Fd
    T=2*pi*r/v


    3. The attempt at a solution
    A)
    positive area + negative area
    1/2*20*4+1/2*(-10)*2
    =30J

    B)
    T=2*pi/V
    V=6.28 m/s
    mg-N=m(v^2)/R
    N=50*9.8-50*(6.28^2)/10
    N=0.29kN

    C)
    T-mg=mv^2/R
    T=(0.5*8^2)/2 +0.5*9.8
    T=41N

    D)
    W=-(2.5*9.8*0.8)
    W=-20J

    E)
    15*12*cos110
    =-62

    It said one of my answer is wrong .
    Thank you
     

    Attached Files:

  2. jcsd
  3. Feb 13, 2016 #2

    TSny

    User Avatar
    Homework Helper
    Gold Member

    Welcome to PF!

    Hint: The sign is incorrect for one of your answers.
     
  4. Feb 13, 2016 #3
    For part D
    It should be mgh instead of -mgh?
     
  5. Feb 13, 2016 #4

    TSny

    User Avatar
    Homework Helper
    Gold Member

    To make sure you understand the sign of the work, use the definition of work: W = F d cosθ. For part D, what would be the values for F, d and θ?
     
  6. Feb 13, 2016 #5
    F is mg
    d is height
    And θ is 0 degree?
    If the object is raise up , the workdone is -mgh?
    the θ also remain 0 but the g become negative?
     
  7. Feb 13, 2016 #6

    TSny

    User Avatar
    Homework Helper
    Gold Member

    Yes
    No, g is always a positive number. θ ≠ 0o for this case. θ is the angle between the force direction and the displacement direction.
     
  8. Feb 13, 2016 #7
    What is the force direction and the displacement direction when it raises up?
    normal force (force direction,upward) and moving upward(displacement direction)?
    How can I get the θ is 180?
     
  9. Feb 13, 2016 #8

    TSny

    User Avatar
    Homework Helper
    Gold Member

    What is the direction of the force of gravity if the object is moving upward?
     
  10. Feb 13, 2016 #9
    the force of gravity is putting downward
    So the force is gravity force instead of normal force in this case?
     
  11. Feb 13, 2016 #10

    TSny

    User Avatar
    Homework Helper
    Gold Member

    If you are finding the work done by the force of gravity, then you use the force of gravity. If you want the work done by the lifting force, then you use the lifting force.
     
  12. Feb 13, 2016 #11
    Thank you
    I get it
     
  13. Feb 13, 2016 #12

    TSny

    User Avatar
    Homework Helper
    Gold Member

    Good work :oldsmile:
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Circular motion and energy
Loading...