Hi. I am a little stuck and I would appreciate some help. What is the acceleration due to gravity of the sun at the distance of 1.6 X 10^11 m? The asteroid revolves around the sun in 398 earth days. 2. Relevant equations: F= (m*V^2)/r 3. The attempt at a solution: First I found the circumference: 1.00 * 10 ^12 m Converted 398 to seconds --> 85968000 sec So I used that to come up with a velocity --> 1.00 * 10 ^12 m/85968000 sec = 11694 m/s And did F= (V^2)/r and came up with .000855 I know I am doing this wrong but I just don't know what to do. Thanks for your help!