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Circular motion ='( and Tension

  1. Nov 17, 2006 #1
    Tarzan (m=85kg) tries to cross a river by swiming from 10.0m long vine. His speed at the bottom of the swing, just as he clears the water, is 8.0m/s. Tarzan doesnt know that the vine has a breaking strength of 1.0*10^3 N. Does he make it safely across the river?

    mass= 85kg
    rope= 10m
    velocity= 8.0m/s
    Tension= 1.0*10^3N
    and it has to do with this equation somehow

    Fc(force that maintains circular motion)
    mass (m)
    Vt^2 (tangential speed)^2
    r (distance to axis)
    w (angular speed)

    Fc=m*((Vt^2)/r) or Fc=m*r*(w)^2

    I know the answer is no but i dont know how to get there
    well thanks again
  2. jcsd
  3. Nov 17, 2006 #2
    While you have a centripetal force, I think you are missing the force from his weight.
  4. Nov 17, 2006 #3


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    Homework Helper

    Physics girl phd is right, you have to count the weight in, and, by the way, by typing 'Tarzan' into the search box, I'm sure you'll find at least two very similar (if not same) problems.
  5. Nov 17, 2006 #4


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    This isn't advanced physics.
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