Circular motion ='( and Tension

[Karex]

Tarzan (m=85kg) tries to cross a river by swiming from 10.0m long vine. His speed at the bottom of the swing, just as he clears the water, is 8.0m/s. Tarzan doesn't know that the vine has a breaking strength of 1.0*10^3 N. Does he make it safely across the river?

mass= 85kg
rope= 10m
velocity= 8.0m/s
Tension= 1.0*10^3N
and it has to do with this equation somehow

Fc(force that maintains circular motion)
mass (m)
Vt^2 (tangential speed)^2
r (distance to axis)
w (angular speed)

Fc=m*((Vt^2)/r) or Fc=m*r*(w)^2

I know the answer is no but i don't know how to get there
well thanks again

 

[physics girl phd]

While you have a centripetal force, I think you are missing the force from his weight.

 

[radou]

Physics girl phd is right, you have to count the weight in, and, by the way, by typing 'Tarzan' into the search box, I'm sure you'll find at least two very similar (if not same) problems.

 

[Gza]

This isn't advanced physics.