- #1
calwyn
- 1
- 0
1. A car of mass 1000kg can take a corner of 50m radius at 10ms-1.
a) Calculate the frictional force provided by the tyres that allows the car to take the corner.
The same car now takes a corner of the same radius but the road is banked inwards at 30 degrees.
b) What is the maximum speed the car can take the corner on the same tyres?
For part a i got 2000N, which is fine. Just need to clear up on part b, coz i don't seem to be able to get it right :(
I used F=Nsin30
= 10000 x .5
= 5000N
V^2= Fr/m
= 5000x50/1000
v = 15.8 ms^-1
a) Calculate the frictional force provided by the tyres that allows the car to take the corner.
The same car now takes a corner of the same radius but the road is banked inwards at 30 degrees.
b) What is the maximum speed the car can take the corner on the same tyres?
The Attempt at a Solution
For part a i got 2000N, which is fine. Just need to clear up on part b, coz i don't seem to be able to get it right :(
I used F=Nsin30
= 10000 x .5
= 5000N
V^2= Fr/m
= 5000x50/1000
v = 15.8 ms^-1