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Circular Motion Bug Question

  1. Mar 21, 2006 #1
    If the coefficient of friction between a bug and the turntable is 0.55 and the bug is 25 cm from the centre, how fast (in RPM) does the turntable have to spin to cause the bug to slide off?

    All I know so far is that the frictional force must be 0 (?)
    Fc = m4pi^2r/T^2
    but this obviously can't work if Ff is 0....so what am I doing wrong?
    thanks in advance
  2. jcsd
  3. Mar 21, 2006 #2
    hey nvm i got it :)
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