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What about any relating the applied force to the period?

- Thread starter JohnSimpson
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- #1

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What about any relating the applied force to the period?

- #2

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[tex] a_{c} = \frac{v^2}{r} [/tex]

the velocity is distance (circumference of the circle) and the time is the period of one rotation

[tex] v = \frac{2 \pi r}{T} [/tex]

then [tex] a_[c} = \frac{4 \pi^2 r}{T^2} [/tex]

multiply acceration by force and taht gives the force period relation

- #3

quasar987

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multiply acceration bystunner5000pt said:multiply acceration by force and taht gives the force period relation

Good analysis stunner !

- #4

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WELL im no expert in this field... one can attest to that

- #5

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And what about the rigid rotators ?stunner5000pt said:

[tex] a_{c} = \frac{v^2}{r} [/tex]

the velocity is distance (circumference of the circle) and the time is the period of one rotation

[tex] v = \frac{2 \pi r}{T} [/tex]

then [tex] a_[c} = \frac{4 \pi^2 r}{T^2} [/tex]

multiply acceration by force and taht gives the force period relation

marlon

- #6

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The given treatment only applies to point particles, not massive rotating objects (ie rigid rotators like a spinning sphere or rod)quasar987 said:I expected that you'd explain things like "what is a rigid rotator" and "how does the treatement of uniform circular motion made by stunner does not apply to it."

Nope, he's not a scientist, he is a far greater genius. You certainly know him.I'd really like to know who is in your avatar, I assume he is some mathematician or physicist who lived some 235 years ago but I've never seen him before.

regards

marlon

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Mozart I believe.

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