1. The problem statement, all variables and given/known data Earth is a spherical object, which completes a full rotation every 24 hours. How long should the day on Earth be so that an object at the equator is able to float freely above the ground? 2. Relevant equations v=2πr/T Fr=mv^2/r v=velocity r= radius T = time for comleting 1 revolution in seconds Fr= centripetal force/force in a radial direction 3. The attempt at a solution 1 revolution in 24 hours so T = 24x3600sec = 86400 Fr=mv^2/r Fr at the earth is equal to mg mg=mv^2/r mass cancels out g=v^2/r Eq. 1 v=2πr/T vT/2π = r Eq. 2 Sub Eq. 2 into 1 g=v^2/(vT/2π) re arrange the equation to v=gT/2π v= 9.8*86400/2π v=134 760m/s Thats where I'm at so far....I'm just not sure if that's correct...and if so where to go from there.