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Introductory Physics Homework Help
Circular motion: net work after one period
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[QUOTE="tia89, post: 4517007, member: 464176"] You are right and you are wrong... the work is indeed zero, but actually not only on a full rounf, every time... indeed the work is the scalar product of the force times the displacement vector... and in an uniform circular motion the acceleration (and hence the force) is the centripetal one only, and is perpendicular ALWAYS to the displacement, so that the scalar product is identically zero [/QUOTE]
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Circular motion: net work after one period
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