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Circular motion of a bucket

  1. Sep 18, 2011 #1

    ama

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    1. The problem statement, all variables and given/known data
    You swing a 6.5 kg bucket of water in a vertical circle of radius 3.6 m.
    What speed must the bucket have if it is to complete the circle without spilling any water?
    mass=6.5 kg
    r= 3.6

    2. Relevant equations
    ay=(v^(2)/(r))
    may= A-N-Mg

    3. The attempt at a solution
    I know that the force of gravity on the water and the normal force of the bucket on the water both point down. I assume you need to get the centripetal acceleration first. But I do not know what the applied force is and have no way of knowing. What do I do?
     
  2. jcsd
  3. Sep 18, 2011 #2
    What would need to happen for the water to stay in the bucket? (something needs to equal something else)
     
  4. Sep 18, 2011 #3

    ama

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    the normal force and gravity must equal the applied force. But if that is the case, then ay is 0 and the problem is unsolvable.
     
  5. Sep 18, 2011 #4
    You need to use centripetal acceleration (or a reaction against it), and acceleration of gravity for this one.
     
  6. Sep 18, 2011 #5

    ama

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    at the top of the path, the normal force the bucket exerts on the water is 0. therefore, applied force, which is equal to normal force, is 0. Thus mg=(m)(v2/r) solving for v gets 5.94 m/s.
     
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