Circular Motion of a bucket

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Homework Statement



A 3.75 kg bucket pile of water is swung in a vertical circle. If the speed of the bucket at the top of the loop is 6.20 m/s, then the radius of the largest circle through which this pail could move without the water leaving the bottom of the pail would be what?

m = 3.75 kg

v = 6.20 m/s

r = ?

I was thinking to use Fc = mv^2/r but I'm not given Fc. I'm not sure what formula I should use or how to go about solving this question. Any help would be greatly appreciated.
 

Answers and Replies

  • #2
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at the top of the loop is 6.20 m/s,
Step 1 read the question. Step 2 is to reread the question for the information you need.
 
  • #3
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Step 1 read the question. Step 2 is to reread the question for the information you need.
What do you mean?
 
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It's stated all over the forum that you are going to have to do some of the work. If I quote a piece of your original post, that is what is called a "hint."
 
  • #5
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Well I sort of figured that. I'm not trying to get out of doing the work, I'm just not sure what formula I should use or how I should go about the question.
 
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Does the question place you specifically on the Moon? Or Mars? Or elsewhere in the solar system? You may assume that you are on the Earth's surface.
 
  • #7
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So g = -9.81. Is Fc equal to Fg or something like that then ?
 
  • #8
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Makes a good place to start.
 

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