# Circular Motion of a bucket

• Redjakk1
In summary, the question asks for the radius of the largest circle that a 3.75 kg bucket of water, moving at a speed of 6.20 m/s at the top of a vertical loop, can move through without the water leaving the bottom of the bucket. The formula Fc = mv^2/r is mentioned, but the value for Fc is not given. It is stated that the question is set on Earth's surface, where the gravitational acceleration is -9.81 m/s^2. A possible starting point for solving the question is to consider the relationship between Fc and Fg.

## Homework Statement

A 3.75 kg bucket pile of water is swung in a vertical circle. If the speed of the bucket at the top of the loop is 6.20 m/s, then the radius of the largest circle through which this pail could move without the water leaving the bottom of the pail would be what?

m = 3.75 kg

v = 6.20 m/s

r = ?

I was thinking to use Fc = mv^2/r but I'm not given Fc. I'm not sure what formula I should use or how to go about solving this question. Any help would be greatly appreciated.

Redjakk1 said:
at the top of the loop is 6.20 m/s,
Step 1 read the question. Step 2 is to reread the question for the information you need.

Bystander said:
Step 1 read the question. Step 2 is to reread the question for the information you need.
What do you mean?

It's stated all over the forum that you are going to have to do some of the work. If I quote a piece of your original post, that is what is called a "hint."

Well I sort of figured that. I'm not trying to get out of doing the work, I'm just not sure what formula I should use or how I should go about the question.

Does the question place you specifically on the Moon? Or Mars? Or elsewhere in the solar system? You may assume that you are on the Earth's surface.

So g = -9.81. Is Fc equal to Fg or something like that then ?

Makes a good place to start.