Circular Motion of a bucket

[Redjakk1]

Homework Statement

A 3.75 kg bucket pile of water is swung in a vertical circle. If the speed of the bucket at the top of the loop is 6.20 m/s, then the radius of the largest circle through which this pail could move without the water leaving the bottom of the pail would be what?

m = 3.75 kg

v = 6.20 m/s

r = ?

I was thinking to use Fc = mv^2/r but I'm not given Fc. I'm not sure what formula I should use or how to go about solving this question. Any help would be greatly appreciated.

 

[Bystander]

at the top of the loop is 6.20 m/s,

Step 1 read the question. Step 2 is to reread the question for the information you need.

 

[Redjakk1]

Step 1 read the question. Step 2 is to reread the question for the information you need.

What do you mean?

 

[Bystander]

It's stated all over the forum that you are going to have to do some of the work. If I quote a piece of your original post, that is what is called a "hint."

 

[Redjakk1]

Well I sort of figured that. I'm not trying to get out of doing the work, I'm just not sure what formula I should use or how I should go about the question.

 

[Bystander]

Does the question place you specifically on the Moon? Or Mars? Or elsewhere in the solar system? You may assume that you are on the Earth's surface.

 

[Redjakk1]

So g = -9.81. Is Fc equal to Fg or something like that then ?

 

[Bystander]

Makes a good place to start.