- #1
Dan22
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Homework Statement
A turntable of radius "r" is spinning counterclockwise at an initial rate of ω. at t=0, its rotation rate begins to slow at a steady pace. the rotation finally stops at t=T. At what time during the time interval 0<t<T was the magnitude of the centripetal acceleration of a point on the turntable's rim equal to half its initial value? Express the answer in terms of T
Homework Equations
centripetal acceleration=ω^2r
ω=ω°+αt ?
Δθ=ω°t+.5αt^2
The Attempt at a Solution
got about a page and a half of hand written notes right here and nothing to show for it. not really sure where to start, and definitely not sure how to right equation in terms of T. any suggestions are appreciated